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2932031007419 is a prime number
BaseRepresentation
bin101010101010101010101…
…010101010101010111011
3101101022002021121200222112
4222222222222222222323
5341014244414214134
610122542332042535
7421555314231623
oct52525252525273
911338067550875
102932031007419
11a3051607a638
123b42b730344b
131836490c82b7
14a1ca7d2b883
15514075bd1ce
hex2aaaaaaaabb

2932031007419 has 2 divisors, whose sum is σ = 2932031007420. Its totient is φ = 2932031007418.

The previous prime is 2932031007403. The next prime is 2932031007421. The reversal of 2932031007419 is 9147001302392.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2932031007419 - 24 = 2932031007403 is a prime.

It is a super-2 number, since 2×29320310074192 (a number of 26 digits) contains 22 as substring.

Together with 2932031007421, it forms a pair of twin primes.

It is a Chen prime.

It is a plaindrome in base 16.

It is not a weakly prime, because it can be changed into another prime (2932031097419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1466015503709 + 1466015503710.

It is an arithmetic number, because the mean of its divisors is an integer number (1466015503710).

Almost surely, 22932031007419 is an apocalyptic number.

2932031007419 is a deficient number, since it is larger than the sum of its proper divisors (1).

2932031007419 is an equidigital number, since it uses as much as digits as its factorization.

2932031007419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81648, while the sum is 41.

The spelling of 2932031007419 in words is "two trillion, nine hundred thirty-two billion, thirty-one million, seven thousand, four hundred nineteen".