Base | Representation |
---|---|
bin | 101010101101101010011… |
… | …001100001110111100111 |
3 | 101101121101110110200001202 |
4 | 222231222121201313213 |
5 | 341042341410143031 |
6 | 10124233441513115 |
7 | 422031114063101 |
oct | 52555231416747 |
9 | 11347343420052 |
10 | 2935247740391 |
11 | a3191691173a |
12 | 3b4a5464279b |
13 | 183a3c6751a5 |
14 | a20d1230571 |
15 | 51544bc42cb |
hex | 2ab6a661de7 |
2935247740391 has 2 divisors, whose sum is σ = 2935247740392. Its totient is φ = 2935247740390.
The previous prime is 2935247740319. The next prime is 2935247740393. The reversal of 2935247740391 is 1930477425392.
Together with previous prime (2935247740319) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2935247740391 - 238 = 2660369833447 is a prime.
Together with 2935247740393, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2935247740393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1467623870195 + 1467623870196.
It is an arithmetic number, because the mean of its divisors is an integer number (1467623870196).
Almost surely, 22935247740391 is an apocalyptic number.
2935247740391 is a deficient number, since it is larger than the sum of its proper divisors (1).
2935247740391 is an equidigital number, since it uses as much as digits as its factorization.
2935247740391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11430720, while the sum is 56.
The spelling of 2935247740391 in words is "two trillion, nine hundred thirty-five billion, two hundred forty-seven million, seven hundred forty thousand, three hundred ninety-one".
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