2938171320000 has 2520 divisors, whose sum is σ = 13170764006400. Its totient is φ = 646652160000.

The previous prime is 2938171319999. The next prime is 2938171320017. The reversal of 2938171320000 is 231718392.

2938171320000 is a `hidden beast` number, since 2 + 9 + 381 + 71 + 3 + 200 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (2520).

It is a super-4 number, since 4×2938171320000⁴ (a number of 51 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 359 ways as a sum of consecutive naturals, for example, 14764679901 + ... + 14764680099.

Almost surely, 2^{2938171320000} is an apocalyptic number.

2938171320000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2938171320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6585382003200).

2938171320000 is an abundant number, since it is smaller than the sum of its proper divisors (10232592686400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2938171320000 is an equidigital number, since it uses as much as digits as its factorization.

2938171320000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 291 (or 247 counting only the distinct ones).

The product of its (nonzero) digits is 18144, while the sum is 36.

The spelling of 2938171320000 in words is "two trillion, nine hundred thirty-eight billion, one hundred seventy-one million, three hundred twenty thousand".