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30001102000141 is a prime number
BaseRepresentation
bin1101101001001001011010…
…00001110001000000001101
310221020002002101022011111011
412310210231001301000031
512413014224103001031
6143450152130525221
76214336163262466
oct664445501610015
9127202071264434
1030001102000141
119617439a52078
1234464b8436811
13139812684043c
1475a0bd889d6d
153705e69076b1
hex1b492d07100d

30001102000141 has 2 divisors, whose sum is σ = 30001102000142. Its totient is φ = 30001102000140.

The previous prime is 30001102000057. The next prime is 30001102000157. The reversal of 30001102000141 is 14100020110003.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22775467693225 + 7225634306916 = 4772365^2 + 2688054^2 .

It is a cyclic number.

It is not a de Polignac number, because 30001102000141 - 215 = 30001101967373 is a prime.

It is a super-2 number, since 2×300011020001412 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (30001102070141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15000551000070 + 15000551000071.

It is an arithmetic number, because the mean of its divisors is an integer number (15000551000071).

Almost surely, 230001102000141 is an apocalyptic number.

It is an amenable number.

30001102000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

30001102000141 is an equidigital number, since it uses as much as digits as its factorization.

30001102000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 30001102000141 its reverse (14100020110003), we get a palindrome (44101122110144).

The spelling of 30001102000141 in words is "thirty trillion, one billion, one hundred two million, one hundred forty-one", and thus it is an aban number.