Base | Representation |
---|---|
bin | 101011101010000101101… |
… | …000011100010100111111 |
3 | 101121210212011021110212221 |
4 | 223222011220130110333 |
5 | 343123231030103002 |
6 | 10214123523310211 |
7 | 426515665651423 |
oct | 53520550342477 |
9 | 11553764243787 |
10 | 3000129144127 |
11 | a57390763665 |
12 | 40554121b367 |
13 | 189bac508c4b |
14 | a52c8112b83 |
15 | 53090c53c37 |
hex | 2ba85a1c53f |
3000129144127 has 2 divisors, whose sum is σ = 3000129144128. Its totient is φ = 3000129144126.
The previous prime is 3000129144121. The next prime is 3000129144139. The reversal of 3000129144127 is 7214419210003.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3000129144127 - 215 = 3000129111359 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3000129144092 and 3000129144101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3000129144121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1500064572063 + 1500064572064.
It is an arithmetic number, because the mean of its divisors is an integer number (1500064572064).
Almost surely, 23000129144127 is an apocalyptic number.
3000129144127 is a deficient number, since it is larger than the sum of its proper divisors (1).
3000129144127 is an equidigital number, since it uses as much as digits as its factorization.
3000129144127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 34.
It can be divided in two parts, 300012914 and 4127, that added together give a square (300017041 = 173212).
The spelling of 3000129144127 in words is "three trillion, one hundred twenty-nine million, one hundred forty-four thousand, one hundred twenty-seven".
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