Base | Representation |
---|---|
bin | 1101101001001001110001… |
… | …11010000101001110110001 |
3 | 10221020002121021100021112220 |
4 | 12310210320322011032301 |
5 | 12413020131113444213 |
6 | 143450224010511253 |
7 | 6214344133354053 |
oct | 664447072051661 |
9 | 127202537307486 |
10 | 30001301312433 |
11 | 9617531505380 |
12 | 3446553135529 |
13 | 1398158c166c9 |
14 | 75a0dc12d8d3 |
15 | 370609177e23 |
hex | 1b4938e853b1 |
30001301312433 has 32 divisors (see below), whose sum is σ = 44576816320512. Its totient is φ = 17791715356800.
The previous prime is 30001301312377. The next prime is 30001301312473. The reversal of 30001301312433 is 33421310310003.
It is a happy number.
It is not a de Polignac number, because 30001301312433 - 224 = 30001284535217 is a prime.
It is not an unprimeable number, because it can be changed into a prime (30001301312473) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4673413 + ... + 9046733.
It is an arithmetic number, because the mean of its divisors is an integer number (1393025510016).
Almost surely, 230001301312433 is an apocalyptic number.
30001301312433 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
30001301312433 is a deficient number, since it is larger than the sum of its proper divisors (14575515008079).
30001301312433 is a wasteful number, since it uses less digits than its factorization.
30001301312433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4377805.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 30001301312433 its reverse (33421310310003), we get a palindrome (63422611622436).
The spelling of 30001301312433 in words is "thirty trillion, one billion, three hundred one million, three hundred twelve thousand, four hundred thirty-three".
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