Base | Representation |
---|---|
bin | 11011111111011000… |
… | …001101011101110111 |
3 | 2212120112112200111011 |
4 | 123333120031131313 |
5 | 443022402343341 |
6 | 21450132453051 |
7 | 2112526451611 |
oct | 337730153567 |
9 | 85515480434 |
10 | 30054340471 |
11 | 11822989911 |
12 | 59a917a187 |
13 | 2aac71001c |
14 | 1651751db1 |
15 | bad7aeb81 |
hex | 6ff60d777 |
30054340471 has 2 divisors, whose sum is σ = 30054340472. Its totient is φ = 30054340470.
The previous prime is 30054340469. The next prime is 30054340483. The reversal of 30054340471 is 17404345003.
It is a weak prime.
It is an emirp because it is prime and its reverse (17404345003) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30054340471 - 21 = 30054340469 is a prime.
It is a super-3 number, since 3×300543404713 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 30054340469, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30054340411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15027170235 + 15027170236.
It is an arithmetic number, because the mean of its divisors is an integer number (15027170236).
Almost surely, 230054340471 is an apocalyptic number.
30054340471 is a deficient number, since it is larger than the sum of its proper divisors (1).
30054340471 is an equidigital number, since it uses as much as digits as its factorization.
30054340471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 31.
Adding to 30054340471 its reverse (17404345003), we get a palindrome (47458685474).
The spelling of 30054340471 in words is "thirty billion, fifty-four million, three hundred forty thousand, four hundred seventy-one".
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