Base | Representation |
---|---|
bin | 101011110100010011100… |
… | …101000010011111011010 |
3 | 101122212011202220200220110 |
4 | 223310103211002133122 |
5 | 343313213220114010 |
6 | 10223140330505150 |
7 | 430354610245650 |
oct | 53642345023732 |
9 | 11585152820813 |
10 | 3011100551130 |
11 | a61000842081 |
12 | 4076a35951b6 |
13 | 18ac3a531b59 |
14 | a5a4929cdd0 |
15 | 534d4046120 |
hex | 2bd139427da |
3011100551130 has 64 divisors (see below), whose sum is σ = 8259158089728. Its totient is φ = 688239935040.
The previous prime is 3011100551117. The next prime is 3011100551167. The reversal of 3011100551130 is 311550011103.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 3011100551097 and 3011100551106.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21642769 + ... + 21781451.
It is an arithmetic number, because the mean of its divisors is an integer number (129049345152).
Almost surely, 23011100551130 is an apocalyptic number.
3011100551130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3011100551130 is an abundant number, since it is smaller than the sum of its proper divisors (5248057538598).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3011100551130 is a wasteful number, since it uses less digits than its factorization.
3011100551130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 242091.
The product of its (nonzero) digits is 225, while the sum is 21.
Adding to 3011100551130 its reverse (311550011103), we get a palindrome (3322650562233).
The spelling of 3011100551130 in words is "three trillion, eleven billion, one hundred million, five hundred fifty-one thousand, one hundred thirty".
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