Base | Representation |
---|---|
bin | 1000110001001111000… |
… | …11011011110010100010 |
3 | 1001210201220101112021120 |
4 | 10120213203123302202 |
5 | 14414041143423020 |
6 | 350230455033110 |
7 | 30524526612453 |
oct | 4304743336242 |
9 | 1053656345246 |
10 | 301311311010 |
11 | 10687041a706 |
12 | 4a49066b796 |
13 | 2254b6c7098 |
14 | 1082536912a |
15 | 7c87885740 |
hex | 46278dbca2 |
301311311010 has 64 divisors (see below), whose sum is σ = 747245481984. Its totient is φ = 77677444800.
The previous prime is 301311310987. The next prime is 301311311017. The reversal of 301311311010 is 10113113103.
It is a super-2 number, since 2×3013113110102 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is not an unprimeable number, because it can be changed into a prime (301311311017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 736197 + ... + 1069863.
It is an arithmetic number, because the mean of its divisors is an integer number (11675710656).
Almost surely, 2301311311010 is an apocalyptic number.
301311311010 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 301311311010, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (373622740992).
301311311010 is an abundant number, since it is smaller than the sum of its proper divisors (445934170974).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
301311311010 is a wasteful number, since it uses less digits than its factorization.
301311311010 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 334679.
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 301311311010 its reverse (10113113103), we get a palindrome (311424424113).
The spelling of 301311311010 in words is "three hundred one billion, three hundred eleven million, three hundred eleven thousand, ten".
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