Base | Representation |
---|---|
bin | 1011001110011001… |
… | …1100110011110101 |
3 | 21202222212110220021 |
4 | 2303212130303311 |
5 | 22132334414031 |
6 | 1214555205141 |
7 | 134445533656 |
oct | 26346346365 |
9 | 7688773807 |
10 | 3013201141 |
11 | 1306967685 |
12 | 7011467b1 |
13 | 390357172 |
14 | 20828152d |
15 | 129800511 |
hex | b399ccf5 |
3013201141 has 2 divisors, whose sum is σ = 3013201142. Its totient is φ = 3013201140.
The previous prime is 3013201039. The next prime is 3013201157. The reversal of 3013201141 is 1411023103.
It is an a-pointer prime, because the next prime (3013201157) can be obtained adding 3013201141 to its sum of digits (16).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2492905041 + 520296100 = 49929^2 + 22810^2 .
It is a cyclic number.
It is not a de Polignac number, because 3013201141 - 215 = 3013168373 is a prime.
It is a super-3 number, since 3×30132011413 (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3013202141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506600570 + 1506600571.
It is an arithmetic number, because the mean of its divisors is an integer number (1506600571).
Almost surely, 23013201141 is an apocalyptic number.
It is an amenable number.
3013201141 is a deficient number, since it is larger than the sum of its proper divisors (1).
3013201141 is an equidigital number, since it uses as much as digits as its factorization.
3013201141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
The square root of 3013201141 is about 54892.6328481336. The cubic root of 3013201141 is about 1444.3619571105.
Adding to 3013201141 its reverse (1411023103), we get a palindrome (4424224244).
The spelling of 3013201141 in words is "three billion, thirteen million, two hundred one thousand, one hundred forty-one".
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