Base | Representation |
---|---|
bin | 100010010000011110010010… |
… | …1101101011110111011000111 |
3 | 1110111220222121102220001112012 |
4 | 1010200330211231132323013 |
5 | 303444002341224401244 |
6 | 2544513355002044435 |
7 | 120320315054122622 |
oct | 10440744555367307 |
9 | 1414828542801465 |
10 | 301331243200199 |
11 | 88016954108423 |
12 | 2996801b7a971b |
13 | cc1a550302b64 |
14 | 545a71d5a2db9 |
15 | 24c84b55cd89e |
hex | 1120f25b5eec7 |
301331243200199 has 2 divisors, whose sum is σ = 301331243200200. Its totient is φ = 301331243200198.
The previous prime is 301331243200189. The next prime is 301331243200201. The reversal of 301331243200199 is 991002342133103.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 301331243200199 - 232 = 301326948232903 is a prime.
Together with 301331243200201, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (301331243200189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150665621600099 + 150665621600100.
It is an arithmetic number, because the mean of its divisors is an integer number (150665621600100).
Almost surely, 2301331243200199 is an apocalyptic number.
301331243200199 is a deficient number, since it is larger than the sum of its proper divisors (1).
301331243200199 is an equidigital number, since it uses as much as digits as its factorization.
301331243200199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 41.
The spelling of 301331243200199 in words is "three hundred one trillion, three hundred thirty-one billion, two hundred forty-three million, two hundred thousand, one hundred ninety-nine".
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