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3014131211489 is a prime number
BaseRepresentation
bin101011110111001000001…
…110000101110011100001
3101200010222222122012100102
4223313020032011303201
5343340420042231424
610224401152232145
7430522660400306
oct53671016056341
911603888565312
103014131211489
11a62316544062
124081aa53b655
1318b30138cac8
14a5c559a70ad
15536101447ae
hex2bdc8385ce1

3014131211489 has 2 divisors, whose sum is σ = 3014131211490. Its totient is φ = 3014131211488.

The previous prime is 3014131211419. The next prime is 3014131211491. The reversal of 3014131211489 is 9841121314103.

3014131211489 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2095010182225 + 919121029264 = 1447415^2 + 958708^2 .

It is a cyclic number.

It is not a de Polignac number, because 3014131211489 - 240 = 1914619583713 is a prime.

Together with 3014131211491, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3014131211419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1507065605744 + 1507065605745.

It is an arithmetic number, because the mean of its divisors is an integer number (1507065605745).

Almost surely, 23014131211489 is an apocalyptic number.

It is an amenable number.

3014131211489 is a deficient number, since it is larger than the sum of its proper divisors (1).

3014131211489 is an equidigital number, since it uses as much as digits as its factorization.

3014131211489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 38.

The spelling of 3014131211489 in words is "three trillion, fourteen billion, one hundred thirty-one million, two hundred eleven thousand, four hundred eighty-nine".