Base | Representation |
---|---|
bin | 11100000100101011… |
… | …101011011100000011 |
3 | 2212210201222211020112 |
4 | 130010223223130003 |
5 | 443213143030201 |
6 | 21503032101535 |
7 | 2114660035502 |
oct | 340453533403 |
9 | 85721884215 |
10 | 30143330051 |
11 | 1186914001a |
12 | 5a12b348ab |
13 | 2ac4c9a093 |
14 | 165d4b8839 |
15 | bb64dc0bb |
hex | 704aeb703 |
30143330051 has 2 divisors, whose sum is σ = 30143330052. Its totient is φ = 30143330050.
The previous prime is 30143330027. The next prime is 30143330053. The reversal of 30143330051 is 15003334103.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30143330051 - 26 = 30143329987 is a prime.
Together with 30143330053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 30143329999 and 30143330026.
It is not a weakly prime, because it can be changed into another prime (30143330053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15071665025 + 15071665026.
It is an arithmetic number, because the mean of its divisors is an integer number (15071665026).
Almost surely, 230143330051 is an apocalyptic number.
30143330051 is a deficient number, since it is larger than the sum of its proper divisors (1).
30143330051 is an equidigital number, since it uses as much as digits as its factorization.
30143330051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 23.
Adding to 30143330051 its reverse (15003334103), we get a palindrome (45146664154).
The spelling of 30143330051 in words is "thirty billion, one hundred forty-three million, three hundred thirty thousand, fifty-one".
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