Base | Representation |
---|---|
bin | 1000110010110000001… |
… | …00010101010000100101 |
3 | 1001212211121221110211212 |
4 | 10121120010111100211 |
5 | 14422223030211011 |
6 | 350443332241205 |
7 | 30553642115345 |
oct | 4313004252045 |
9 | 1055747843755 |
10 | 302125241381 |
11 | 107148905637 |
12 | 4a679170205 |
13 | 2264b2167a2 |
14 | 108a14bcd25 |
15 | 7cd406008b |
hex | 4658115425 |
302125241381 has 2 divisors, whose sum is σ = 302125241382. Its totient is φ = 302125241380.
The previous prime is 302125241351. The next prime is 302125241393. The reversal of 302125241381 is 183142521203.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 286765605025 + 15359636356 = 535505^2 + 123934^2 .
It is a cyclic number.
It is not a de Polignac number, because 302125241381 - 26 = 302125241317 is a prime.
It is a super-2 number, since 2×3021252413812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (302125241351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 151062620690 + 151062620691.
It is an arithmetic number, because the mean of its divisors is an integer number (151062620691).
Almost surely, 2302125241381 is an apocalyptic number.
It is an amenable number.
302125241381 is a deficient number, since it is larger than the sum of its proper divisors (1).
302125241381 is an equidigital number, since it uses as much as digits as its factorization.
302125241381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 302125241381 its reverse (183142521203), we get a palindrome (485267762584).
The spelling of 302125241381 in words is "three hundred two billion, one hundred twenty-five million, two hundred forty-one thousand, three hundred eighty-one".
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