30243333334241 has 2 divisors, whose sum is σ = 30243333334242. Its totient is φ = 30243333334240.

The previous prime is 30243333334199. The next prime is 30243333334243. The reversal of 30243333334241 is 14243333334203.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21555406128400 + 8687927205841 = 4642780^2 + 2947529^2 .

It is an emirp because it is prime and its reverse (14243333334203) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 30243333334241 - 2²² = 30243329139937 is a prime.

It is a super-2 number, since 2×30243333334241² (a number of 28 digits) contains 22 as substring.

Together with 30243333334243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 30243333334195 and 30243333334204.

It is not a weakly prime, because it can be changed into another prime (30243333334243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15121666667120 + 15121666667121.

It is an arithmetic number, because the mean of its divisors is an integer number (15121666667121).

Almost surely, 2^{30243333334241} is an apocalyptic number.

It is an amenable number.

30243333334241 is a deficient number, since it is larger than the sum of its proper divisors (1).

30243333334241 is an equidigital number, since it uses as much as digits as its factorization.

30243333334241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 38.

Subtracting from 30243333334241 its sum of digits (38), we obtain a palindrome (30243333334203).

Adding to 30243333334241 its reverse (14243333334203), we get a palindrome (44486666668444).

The spelling of 30243333334241 in words is "thirty trillion, two hundred forty-three billion, three hundred thirty-three million, three hundred thirty-four thousand, two hundred forty-one".