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3030954223117 is a prime number
BaseRepresentation
bin101100000110110010111…
…100110010011000001101
3101201202102102002201212011
4230012302330302120031
5344124343240114432
610240222351541221
7431656604545402
oct54066274623015
911652372081764
103030954223117
11a69469707757
1240b50452a811
1318ca827c5062
14a69add742a9
1553c9700a847
hex2c1b2f3260d

3030954223117 has 2 divisors, whose sum is σ = 3030954223118. Its totient is φ = 3030954223116.

The previous prime is 3030954223109. The next prime is 3030954223133. The reversal of 3030954223117 is 7113224590303.

It is a happy number.

3030954223117 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2462730737481 + 568223485636 = 1569309^2 + 753806^2 .

It is a cyclic number.

It is not a de Polignac number, because 3030954223117 - 23 = 3030954223109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3030954223117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3030954220117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1515477111558 + 1515477111559.

It is an arithmetic number, because the mean of its divisors is an integer number (1515477111559).

Almost surely, 23030954223117 is an apocalyptic number.

It is an amenable number.

3030954223117 is a deficient number, since it is larger than the sum of its proper divisors (1).

3030954223117 is an equidigital number, since it uses as much as digits as its factorization.

3030954223117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 40.

The spelling of 3030954223117 in words is "three trillion, thirty billion, nine hundred fifty-four million, two hundred twenty-three thousand, one hundred seventeen".