Base | Representation |
---|---|
bin | 101100000111111101010… |
… | …010011110100100010101 |
3 | 101201212122022221001122001 |
4 | 230013331102132210111 |
5 | 344134422031020000 |
6 | 10240550223435301 |
7 | 432032530560130 |
oct | 54077522364425 |
9 | 11655568831561 |
10 | 3032201423125 |
11 | a69a49721566 |
12 | 40b7b2155b31 |
13 | 18cc21004324 |
14 | a6a8b86d217 |
15 | 53d1b76b46a |
hex | 2c1fd49e915 |
3032201423125 has 40 divisors (see below), whose sum is σ = 4343414812352. Its totient is φ = 2072941200000.
The previous prime is 3032201423107. The next prime is 3032201423129. The reversal of 3032201423125 is 5213241022303.
It is a happy number.
It is not a de Polignac number, because 3032201423125 - 225 = 3032167868693 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3032201423093 and 3032201423102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3032201423129) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 401185 + ... + 2495065.
Almost surely, 23032201423125 is an apocalyptic number.
3032201423125 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
3032201423125 is a deficient number, since it is larger than the sum of its proper divisors (1311213389227).
3032201423125 is an equidigital number, since it uses as much as digits as its factorization.
3032201423125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2094239 (or 2094224 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 3032201423125 its reverse (5213241022303), we get a palindrome (8245442445428).
The spelling of 3032201423125 in words is "three trillion, thirty-two billion, two hundred one million, four hundred twenty-three thousand, one hundred twenty-five".
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