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30402222500125 = 5372347533891559
BaseRepresentation
bin1101110100110100100011…
…01011000010100100011101
310222122102110011021211111101
412322122101223002210131
512441102222430001000
6144354331015153101
76255326262260350
oct672322153024435
9128572404254441
1030402222500125
119761568020713
1234b01a2975791
1313c6bc0359308
147716927a6297
1537ac71885e6a
hex1ba691ac291d

30402222500125 has 256 divisors, whose sum is σ = 47233489305600. Its totient is φ = 19086851097600.

The previous prime is 30402222500077. The next prime is 30402222500179. The reversal of 30402222500125 is 52100522220403.

It is not a de Polignac number, because 30402222500125 - 219 = 30402221975837 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 30402222500093 and 30402222500102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 19501104096 + ... + 19501105654.

It is an arithmetic number, because the mean of its divisors is an integer number (184505817600).

Almost surely, 230402222500125 is an apocalyptic number.

30402222500125 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

It is an amenable number.

30402222500125 is a deficient number, since it is larger than the sum of its proper divisors (16831266805475).

30402222500125 is a wasteful number, since it uses less digits than its factorization.

30402222500125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2093 (or 2083 counting only the distinct ones).

The product of its (nonzero) digits is 9600, while the sum is 28.

Adding to 30402222500125 its reverse (52100522220403), we get a palindrome (82502744720528).

The spelling of 30402222500125 in words is "thirty trillion, four hundred two billion, two hundred twenty-two million, five hundred thousand, one hundred twenty-five".