Base | Representation |
---|---|
bin | 1101110100110100100011… |
… | …10101110001101110001101 |
3 | 10222122102110100120211100221 |
4 | 12322122101311301232031 |
5 | 12441102224140032301 |
6 | 144354331155351341 |
7 | 6255326325222202 |
oct | 672322165615615 |
9 | 128572410524327 |
10 | 30402225314701 |
11 | 9761569673309 |
12 | 34b01a38b2551 |
13 | 13c6bc0b03446 |
14 | 771692cd9ca9 |
15 | 37ac71c3eda1 |
hex | 1ba691d71b8d |
30402225314701 has 2 divisors, whose sum is σ = 30402225314702. Its totient is φ = 30402225314700.
The previous prime is 30402225314693. The next prime is 30402225314719. The reversal of 30402225314701 is 10741352220403.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15288021800100 + 15114203514601 = 3909990^2 + 3887699^2 .
It is a cyclic number.
It is not a de Polignac number, because 30402225314701 - 23 = 30402225314693 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30402225314771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15201112657350 + 15201112657351.
It is an arithmetic number, because the mean of its divisors is an integer number (15201112657351).
Almost surely, 230402225314701 is an apocalyptic number.
It is an amenable number.
30402225314701 is a deficient number, since it is larger than the sum of its proper divisors (1).
30402225314701 is an equidigital number, since it uses as much as digits as its factorization.
30402225314701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40320, while the sum is 34.
The spelling of 30402225314701 in words is "thirty trillion, four hundred two billion, two hundred twenty-five million, three hundred fourteen thousand, seven hundred one".
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