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3040355455391 is a prime number
BaseRepresentation
bin101100001111100011010…
…011101001000110011111
3101202122200121011211002002
4230033203103221012133
5344303121444033031
610244415304552515
7432441561653012
oct54174323510637
911678617154062
103040355455391
11a72453435701
124112a8a8273b
131909204287a7
14a7222791379
1554147540ccb
hex2c3e34e919f

3040355455391 has 2 divisors, whose sum is σ = 3040355455392. Its totient is φ = 3040355455390.

The previous prime is 3040355455373. The next prime is 3040355455399. The reversal of 3040355455391 is 1935545530403.

3040355455391 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (1935545530403) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3040355455391 - 26 = 3040355455327 is a prime.

It is a super-2 number, since 2×30403554553912 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3040355455399) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520177727695 + 1520177727696.

It is an arithmetic number, because the mean of its divisors is an integer number (1520177727696).

Almost surely, 23040355455391 is an apocalyptic number.

3040355455391 is a deficient number, since it is larger than the sum of its proper divisors (1).

3040355455391 is an equidigital number, since it uses as much as digits as its factorization.

3040355455391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2430000, while the sum is 47.

The spelling of 3040355455391 in words is "three trillion, forty billion, three hundred fifty-five million, four hundred fifty-five thousand, three hundred ninety-one".