Base | Representation |
---|---|
bin | 1101110101000110111111… |
… | …10110011010111110100111 |
3 | 10222200101000012210020021012 |
4 | 12322203133312122332213 |
5 | 12441233012223304002 |
6 | 144403045323412435 |
7 | 6256126533056003 |
oct | 672433766327647 |
9 | 128611005706235 |
10 | 30412124041127 |
11 | 97657891a6a54 |
12 | 34b20a698411b |
13 | 13c7b0a82250a |
14 | 771d51819703 |
15 | 37b150c95d52 |
hex | 1ba8dfd9afa7 |
30412124041127 has 2 divisors, whose sum is σ = 30412124041128. Its totient is φ = 30412124041126.
The previous prime is 30412124041081. The next prime is 30412124041141. The reversal of 30412124041127 is 72114042121403.
It is a strong prime.
It is an emirp because it is prime and its reverse (72114042121403) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30412124041127 - 220 = 30412122992551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30412124041093 and 30412124041102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30412124041177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15206062020563 + 15206062020564.
It is an arithmetic number, because the mean of its divisors is an integer number (15206062020564).
Almost surely, 230412124041127 is an apocalyptic number.
30412124041127 is a deficient number, since it is larger than the sum of its proper divisors (1).
30412124041127 is an equidigital number, since it uses as much as digits as its factorization.
30412124041127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 32.
The spelling of 30412124041127 in words is "thirty trillion, four hundred twelve billion, one hundred twenty-four million, forty-one thousand, one hundred twenty-seven".
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