Base | Representation |
---|---|
bin | 101100010000011100010… |
… | …110001011100010000101 |
3 | 101202202011021212202111121 |
4 | 230100130112023202011 |
5 | 344312101440001041 |
6 | 10245054252033541 |
7 | 432504362023126 |
oct | 54203426134205 |
9 | 11682137782447 |
10 | 3041312422021 |
11 | a728a4636915 |
12 | 4115154628b1 |
13 | 190a43779533 |
14 | a72b38da04d |
15 | 541a15717d1 |
hex | 2c41c58b885 |
3041312422021 has 2 divisors, whose sum is σ = 3041312422022. Its totient is φ = 3041312422020.
The previous prime is 3041312422007. The next prime is 3041312422051. The reversal of 3041312422021 is 1202242131403.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3040789613796 + 522808225 = 1743786^2 + 22865^2 .
It is a cyclic number.
It is not a de Polignac number, because 3041312422021 - 25 = 3041312421989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3041312422051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520656211010 + 1520656211011.
It is an arithmetic number, because the mean of its divisors is an integer number (1520656211011).
Almost surely, 23041312422021 is an apocalyptic number.
It is an amenable number.
3041312422021 is a deficient number, since it is larger than the sum of its proper divisors (1).
3041312422021 is an equidigital number, since it uses as much as digits as its factorization.
3041312422021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 3041312422021 its reverse (1202242131403), we get a palindrome (4243554553424).
The spelling of 3041312422021 in words is "three trillion, forty-one billion, three hundred twelve million, four hundred twenty-two thousand, twenty-one".
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