Base | Representation |
---|---|
bin | 11100010101111101… |
… | …001110100101010001 |
3 | 2220112221022212000221 |
4 | 130111331032211101 |
5 | 444311341034441 |
6 | 21551503513041 |
7 | 2125106306533 |
oct | 342575164521 |
9 | 86487285027 |
10 | 30433143121 |
11 | 119a7796957 |
12 | 5a93bb8781 |
13 | 2b4003c1c4 |
14 | 1689b99853 |
15 | bd1b878d1 |
hex | 715f4e951 |
30433143121 has 2 divisors, whose sum is σ = 30433143122. Its totient is φ = 30433143120.
The previous prime is 30433143119. The next prime is 30433143131. The reversal of 30433143121 is 12134133403.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17451731025 + 12981412096 = 132105^2 + 113936^2 .
It is a cyclic number.
It is not a de Polignac number, because 30433143121 - 21 = 30433143119 is a prime.
Together with 30433143119, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (30433143131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15216571560 + 15216571561.
It is an arithmetic number, because the mean of its divisors is an integer number (15216571561).
Almost surely, 230433143121 is an apocalyptic number.
It is an amenable number.
30433143121 is a deficient number, since it is larger than the sum of its proper divisors (1).
30433143121 is an equidigital number, since it uses as much as digits as its factorization.
30433143121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 30433143121 its reverse (12134133403), we get a palindrome (42567276524).
The spelling of 30433143121 in words is "thirty billion, four hundred thirty-three million, one hundred forty-three thousand, one hundred twenty-one".
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