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30503011429997 is a prime number
BaseRepresentation
bin1101110111110000010010…
…01010010010111001101101
311000000001121022102222001222
412323320021022102321231
512444230131411224442
6144512520123513125
76265525026115061
oct673701112227155
9130001538388058
1030503011429997
1197a0288816477
1235078309887a5
131403563443c62
147764d450daa1
1537d6beeac8d2
hex1bbe09292e6d

30503011429997 has 2 divisors, whose sum is σ = 30503011429998. Its totient is φ = 30503011429996.

The previous prime is 30503011429879. The next prime is 30503011430039. The reversal of 30503011429997 is 79992411030503.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28942183482436 + 1560827947561 = 5379794^2 + 1249331^2 .

It is an emirp because it is prime and its reverse (79992411030503) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 30503011429997 - 214 = 30503011413613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (30503011429697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15251505714998 + 15251505714999.

It is an arithmetic number, because the mean of its divisors is an integer number (15251505714999).

Almost surely, 230503011429997 is an apocalyptic number.

It is an amenable number.

30503011429997 is a deficient number, since it is larger than the sum of its proper divisors (1).

30503011429997 is an equidigital number, since it uses as much as digits as its factorization.

30503011429997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1837080, while the sum is 53.

The spelling of 30503011429997 in words is "thirty trillion, five hundred three billion, eleven million, four hundred twenty-nine thousand, nine hundred ninety-seven".