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30504251520133 is a prime number
BaseRepresentation
bin1101110111110010100110…
…00100110111010010000101
311000000011210201220001221021
412323321103010313102011
512444240201342121013
6144513243143151141
76265600534525156
oct673712304672205
9130004721801837
1030504251520133
1197a0864814556
123507b181454b1
131403700333cc1
147765b10b792d
1537d743cb6a8d
hex1bbe53137485

30504251520133 has 2 divisors, whose sum is σ = 30504251520134. Its totient is φ = 30504251520132.

The previous prime is 30504251520091. The next prime is 30504251520139. The reversal of 30504251520133 is 33102515240503.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30487426057764 + 16825462369 = 5521542^2 + 129713^2 .

It is a cyclic number.

It is not a de Polignac number, because 30504251520133 - 217 = 30504251389061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (30504251520139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15252125760066 + 15252125760067.

It is an arithmetic number, because the mean of its divisors is an integer number (15252125760067).

Almost surely, 230504251520133 is an apocalyptic number.

It is an amenable number.

30504251520133 is a deficient number, since it is larger than the sum of its proper divisors (1).

30504251520133 is an equidigital number, since it uses as much as digits as its factorization.

30504251520133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 30504251520133 its reverse (33102515240503), we get a palindrome (63606766760636).

The spelling of 30504251520133 in words is "thirty trillion, five hundred four billion, two hundred fifty-one million, five hundred twenty thousand, one hundred thirty-three".