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30533352001 is a prime number
BaseRepresentation
bin11100011011111011…
…011111101001000001
32220210220212222202221
4130123323133221001
51000013014231001
622005443411041
72130434131645
oct343373375101
986726788687
1030533352001
1111a49310309
125b01683a81
132b57a26ab9
141699202c25
15bda87e1a1
hex71bedfa41

30533352001 has 2 divisors, whose sum is σ = 30533352002. Its totient is φ = 30533352000.

The previous prime is 30533351987. The next prime is 30533352007. The reversal of 30533352001 is 10025333503.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25720461376 + 4812890625 = 160376^2 + 69375^2 .

It is an emirp because it is prime and its reverse (10025333503) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-30533352001 is a prime.

It is not a weakly prime, because it can be changed into another prime (30533352007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15266676000 + 15266676001.

It is an arithmetic number, because the mean of its divisors is an integer number (15266676001).

Almost surely, 230533352001 is an apocalyptic number.

It is an amenable number.

30533352001 is a deficient number, since it is larger than the sum of its proper divisors (1).

30533352001 is an equidigital number, since it uses as much as digits as its factorization.

30533352001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4050, while the sum is 25.

Adding to 30533352001 its reverse (10025333503), we get a palindrome (40558685504).

The spelling of 30533352001 in words is "thirty billion, five hundred thirty-three million, three hundred fifty-two thousand, one".