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3053472242143 is a prime number
BaseRepresentation
bin101100011011110001001…
…000001101100111011111
3101210220112201201121211211
4230123301020031213133
5400012002343222033
610254425031125251
7433414613546551
oct54336110154737
911726481647754
103053472242143
11a77a74527734
12413949813827
13191c30a6a97b
14a7b0883b4d1
1554663d612cd
hex2c6f120d9df

3053472242143 has 2 divisors, whose sum is σ = 3053472242144. Its totient is φ = 3053472242142.

The previous prime is 3053472242113. The next prime is 3053472242147. The reversal of 3053472242143 is 3412422743503.

It is a strong prime.

It is an emirp because it is prime and its reverse (3412422743503) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3053472242143 - 241 = 854448986591 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3053472242096 and 3053472242105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3053472242147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526736121071 + 1526736121072.

It is an arithmetic number, because the mean of its divisors is an integer number (1526736121072).

Almost surely, 23053472242143 is an apocalyptic number.

3053472242143 is a deficient number, since it is larger than the sum of its proper divisors (1).

3053472242143 is an equidigital number, since it uses as much as digits as its factorization.

3053472242143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 483840, while the sum is 40.

Adding to 3053472242143 its reverse (3412422743503), we get a palindrome (6465894985646).

The spelling of 3053472242143 in words is "three trillion, fifty-three billion, four hundred seventy-two million, two hundred forty-two thousand, one hundred forty-three".