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3412422743503 is a prime number
BaseRepresentation
bin110001101010000100001…
…111101101010111001111
3110002020001121102101212011
4301222010033231113033
5421402120210243003
611131351222122051
7501353005510144
oct61520417552717
913066047371764
103412422743503
1110a622274a144
12471425580327
131b9a36a78437
14bb23acbc3cb
155db71a6546d
hex31a843ed5cf

3412422743503 has 2 divisors, whose sum is σ = 3412422743504. Its totient is φ = 3412422743502.

The previous prime is 3412422743461. The next prime is 3412422743507. The reversal of 3412422743503 is 3053472242143.

It is a strong prime.

It is an emirp because it is prime and its reverse (3053472242143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3412422743503 - 213 = 3412422735311 is a prime.

It is a super-2 number, since 2×34124227435032 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3412422743507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706211371751 + 1706211371752.

It is an arithmetic number, because the mean of its divisors is an integer number (1706211371752).

Almost surely, 23412422743503 is an apocalyptic number.

3412422743503 is a deficient number, since it is larger than the sum of its proper divisors (1).

3412422743503 is an equidigital number, since it uses as much as digits as its factorization.

3412422743503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 483840, while the sum is 40.

Adding to 3412422743503 its reverse (3053472242143), we get a palindrome (6465894985646).

The spelling of 3412422743503 in words is "three trillion, four hundred twelve billion, four hundred twenty-two million, seven hundred forty-three thousand, five hundred three".