Base | Representation |
---|---|
bin | 101100011011110100110… |
… | …100111111111001011011 |
3 | 101210220201001112012112021 |
4 | 230123310310333321123 |
5 | 400012114241022300 |
6 | 10254435125355311 |
7 | 433416266263360 |
oct | 54336464777133 |
9 | 11726631465467 |
10 | 3053534314075 |
11 | a77aa6573253 |
12 | 413966568b37 |
13 | 191c40891a1b |
14 | a7b12b98467 |
15 | 54669522d1a |
hex | 2c6f4d3fe5b |
3053534314075 has 96 divisors (see below), whose sum is σ = 4423753433088. Its totient is φ = 2047610880000.
The previous prime is 3053534314073. The next prime is 3053534314091. The reversal of 3053534314075 is 5704134353503.
It is a happy number.
It is not a de Polignac number, because 3053534314075 - 21 = 3053534314073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3053534314073) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2652939750 + ... + 2652940900.
It is an arithmetic number, because the mean of its divisors is an integer number (46080764928).
Almost surely, 23053534314075 is an apocalyptic number.
3053534314075 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
3053534314075 is a deficient number, since it is larger than the sum of its proper divisors (1370219119013).
3053534314075 is a wasteful number, since it uses less digits than its factorization.
3053534314075 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2453 (or 2448 counting only the distinct ones).
The product of its (nonzero) digits is 1134000, while the sum is 43.
Adding to 3053534314075 its reverse (5704134353503), we get a palindrome (8757668667578).
The spelling of 3053534314075 in words is "three trillion, fifty-three billion, five hundred thirty-four million, three hundred fourteen thousand, seventy-five".
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