Base | Representation |
---|---|
bin | 101100011100011000101… |
… | …000111011111000000011 |
3 | 101210222020221001220022002 |
4 | 230130120220323320003 |
5 | 400014332043203101 |
6 | 10255014511134215 |
7 | 433440213166202 |
oct | 54343050737003 |
9 | 11728227056262 |
10 | 3054135131651 |
11 | a7828472a3aa |
12 | 413ab381436b |
13 | 1920081b5796 |
14 | a7b6c8b5239 |
15 | 546a2152d6b |
hex | 2c718a3be03 |
3054135131651 has 2 divisors, whose sum is σ = 3054135131652. Its totient is φ = 3054135131650.
The previous prime is 3054135131633. The next prime is 3054135131653. The reversal of 3054135131651 is 1561315314503.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3054135131651 is a prime.
It is a super-2 number, since 2×30541351316512 (a number of 26 digits) contains 22 as substring.
Together with 3054135131653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3054135131653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527067565825 + 1527067565826.
It is an arithmetic number, because the mean of its divisors is an integer number (1527067565826).
Almost surely, 23054135131651 is an apocalyptic number.
3054135131651 is a deficient number, since it is larger than the sum of its proper divisors (1).
3054135131651 is an equidigital number, since it uses as much as digits as its factorization.
3054135131651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 38.
The spelling of 3054135131651 in words is "three trillion, fifty-four billion, one hundred thirty-five million, one hundred thirty-one thousand, six hundred fifty-one".
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