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305425640433701 is a prime number
BaseRepresentation
bin100010101110010000111001…
…0110011011010100000100101
31111001102101222000122001221202
41011130201302303122200211
5310013043202422334301
63001330334024252245
7121222163044306244
oct10534416263324045
91431371860561852
10305425640433701
118935531765a757
122a309651011085
131015668bc25578
14555c9737d895b
152549c4d9a466b
hex115c872cda825

305425640433701 has 2 divisors, whose sum is σ = 305425640433702. Its totient is φ = 305425640433700.

The previous prime is 305425640433677. The next prime is 305425640433773. The reversal of 305425640433701 is 107334046524503.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 225077256630625 + 80348383803076 = 15002575^2 + 8963726^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-305425640433701 is a prime.

It is a super-2 number, since 2×3054256404337012 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (305425640453701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 152712820216850 + 152712820216851.

It is an arithmetic number, because the mean of its divisors is an integer number (152712820216851).

Almost surely, 2305425640433701 is an apocalyptic number.

It is an amenable number.

305425640433701 is a deficient number, since it is larger than the sum of its proper divisors (1).

305425640433701 is an equidigital number, since it uses as much as digits as its factorization.

305425640433701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3628800, while the sum is 47.

The spelling of 305425640433701 in words is "three hundred five trillion, four hundred twenty-five billion, six hundred forty million, four hundred thirty-three thousand, seven hundred one".