Base | Representation |
---|---|
bin | 101100011100100100010… |
… | …101011011001110011111 |
3 | 101210222202121021111201210 |
4 | 230130210111123032133 |
5 | 400020232311000100 |
6 | 10255050200435503 |
7 | 433445115026205 |
oct | 54344425331637 |
9 | 11728677244653 |
10 | 3054331343775 |
11 | a78375465488 |
12 | 413b49478b93 |
13 | 192039a4492a |
14 | a7b8a98d075 |
15 | 546b44aec50 |
hex | 2c72455b39f |
3054331343775 has 48 divisors (see below), whose sum is σ = 5271886461600. Its totient is φ = 1558375580160.
The previous prime is 3054331343719. The next prime is 3054331343797. The reversal of 3054331343775 is 5773431334503.
It is a happy number.
It is not a de Polignac number, because 3054331343775 - 211 = 3054331341727 is a prime.
It is a super-3 number, since 3×30543313437753 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6204624 + ... + 6678773.
It is an arithmetic number, because the mean of its divisors is an integer number (109830967950).
Almost surely, 23054331343775 is an apocalyptic number.
3054331343775 is a deficient number, since it is larger than the sum of its proper divisors (2217555117825).
3054331343775 is a wasteful number, since it uses less digits than its factorization.
3054331343775 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12883548 (or 12883543 counting only the distinct ones).
The product of its (nonzero) digits is 4762800, while the sum is 48.
The spelling of 3054331343775 in words is "three trillion, fifty-four billion, three hundred thirty-one million, three hundred forty-three thousand, seven hundred seventy-five".
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