Base | Representation |
---|---|
bin | 100010101110011100011100… |
… | …0011100011011110101001010 |
3 | 1111001111202221201201011222210 |
4 | 1011130320320130123311022 |
5 | 310013444440332310200 |
6 | 3001345554011125550 |
7 | 121224031300634415 |
oct | 10534707034336512 |
9 | 1431452851634883 |
10 | 305450431135050 |
11 | 89364889332593 |
12 | 2a31240b4438b6 |
13 | 10158b0cc9a216 |
14 | 555dc4605cb7c |
15 | 254a7000d2650 |
hex | 115ce3871bd4a |
305450431135050 has 48 divisors (see below), whose sum is σ = 757525337587872. Its totient is φ = 81452559230400.
The previous prime is 305450431135033. The next prime is 305450431135063. The reversal of 305450431135050 is 50531134054503.
It is a super-3 number, since 3×3054504311350503 (a number of 44 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2732145 + ... + 24866955.
It is an arithmetic number, because the mean of its divisors is an integer number (15781777866414).
Almost surely, 2305450431135050 is an apocalyptic number.
305450431135050 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
305450431135050 is an abundant number, since it is smaller than the sum of its proper divisors (452074906452822).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
305450431135050 is a wasteful number, since it uses less digits than its factorization.
305450431135050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22226823 (or 22226818 counting only the distinct ones).
The product of its (nonzero) digits is 270000, while the sum is 39.
Adding to 305450431135050 its reverse (50531134054503), we get a palindrome (355981565189553).
The spelling of 305450431135050 in words is "three hundred five trillion, four hundred fifty billion, four hundred thirty-one million, one hundred thirty-five thousand, fifty".
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