Base | Representation |
---|---|
bin | 1101111001010001001110… |
… | …00101001000010101110010 |
3 | 11000012000221011211122022111 |
4 | 12330220213011020111302 |
5 | 13001103222032000200 |
6 | 144552444135155534 |
7 | 6302346461140105 |
oct | 674504705102562 |
9 | 130160834748274 |
10 | 30555053000050 |
11 | 98103639392a7 |
12 | 3515935515baa |
13 | 14084381543a7 |
14 | 778c3003a73c |
15 | 37ec18bc70ba |
hex | 1bca27148572 |
30555053000050 has 24 divisors (see below), whose sum is σ = 56832558773616. Its totient is φ = 12221986749840.
The previous prime is 30555053000041. The next prime is 30555053000053. The reversal of 30555053000050 is 5000035055503.
It is a super-2 number, since 2×305550530000502 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 30555052999976 and 30555053000021.
It is not an unprimeable number, because it can be changed into a prime (30555053000053) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 24377989 + ... + 25600711.
It is an arithmetic number, because the mean of its divisors is an integer number (2368023282234).
Almost surely, 230555053000050 is an apocalyptic number.
30555053000050 is a deficient number, since it is larger than the sum of its proper divisors (26277505773566).
30555053000050 is a wasteful number, since it uses less digits than its factorization.
30555053000050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1722522 (or 1722517 counting only the distinct ones).
The product of its (nonzero) digits is 28125, while the sum is 31.
Adding to 30555053000050 its reverse (5000035055503), we get a palindrome (35555088055553).
The spelling of 30555053000050 in words is "thirty trillion, five hundred fifty-five billion, fifty-three million, fifty", and thus it is an aban number.
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