30840682604621 has 2 divisors, whose sum is σ = 30840682604622. Its totient is φ = 30840682604620.

The previous prime is 30840682604561. The next prime is 30840682604623. The reversal of 30840682604621 is 12640628604803.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26742240264100 + 4098442340521 = 5171290^2 + 2024461^2 .

It is an emirp because it is prime and its reverse (12640628604803) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 30840682604621 - 2¹⁰ = 30840682603597 is a prime.

It is a super-3 number, since 3×30840682604621³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 30840682604623, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 30840682604621.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (30840682604623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15420341302310 + 15420341302311.

It is an arithmetic number, because the mean of its divisors is an integer number (15420341302311).

Almost surely, 2^{30840682604621} is an apocalyptic number.

It is an amenable number.

30840682604621 is a deficient number, since it is larger than the sum of its proper divisors (1).

30840682604621 is an equidigital number, since it uses as much as digits as its factorization.

30840682604621 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2654208, while the sum is 50.

The spelling of 30840682604621 in words is "thirty trillion, eight hundred forty billion, six hundred eighty-two million, six hundred four thousand, six hundred twenty-one".