Base | Representation |
---|---|
bin | 1001000001011111101… |
… | …10110011011110000101 |
3 | 1002122021020222100202021 |
4 | 10200233312303132011 |
5 | 20034430334303221 |
6 | 354233004443141 |
7 | 31254044054656 |
oct | 4405766633605 |
9 | 1078236870667 |
10 | 310040541061 |
11 | 10a53a891419 |
12 | 50107b494b1 |
13 | 23310041c74 |
14 | 1101281952d |
15 | 80e8dc9041 |
hex | 482fdb3785 |
310040541061 has 2 divisors, whose sum is σ = 310040541062. Its totient is φ = 310040541060.
The previous prime is 310040540969. The next prime is 310040541119. The reversal of 310040541061 is 160145040013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 299181650625 + 10858890436 = 546975^2 + 104206^2 .
It is a cyclic number.
It is not a de Polignac number, because 310040541061 - 211 = 310040539013 is a prime.
It is a super-2 number, since 2×3100405410612 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (310040544061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155020270530 + 155020270531.
It is an arithmetic number, because the mean of its divisors is an integer number (155020270531).
Almost surely, 2310040541061 is an apocalyptic number.
It is an amenable number.
310040541061 is a deficient number, since it is larger than the sum of its proper divisors (1).
310040541061 is an equidigital number, since it uses as much as digits as its factorization.
310040541061 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 310040541061 its reverse (160145040013), we get a palindrome (470185581074).
The spelling of 310040541061 in words is "three hundred ten billion, forty million, five hundred forty-one thousand, sixty-one".
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