Base | Representation |
---|---|
bin | 11100111000000100… |
… | …010111110001101101 |
3 | 2222000211012121022121 |
4 | 130320010113301231 |
5 | 1001444343104013 |
6 | 22124350112541 |
7 | 2145225621052 |
oct | 347004276155 |
9 | 88024177277 |
10 | 31005441133 |
11 | 12170843917 |
12 | 60137ab751 |
13 | 2c01788a94 |
14 | 1701bb1029 |
15 | c1703258d |
hex | 738117c6d |
31005441133 has 2 divisors, whose sum is σ = 31005441134. Its totient is φ = 31005441132.
The previous prime is 31005441121. The next prime is 31005441161. The reversal of 31005441133 is 33114450013.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30113702089 + 891739044 = 173533^2 + 29862^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31005441133 is a prime.
It is a super-2 number, since 2×310054411332 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31005441098 and 31005441107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31005441113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15502720566 + 15502720567.
It is an arithmetic number, because the mean of its divisors is an integer number (15502720567).
Almost surely, 231005441133 is an apocalyptic number.
It is an amenable number.
31005441133 is a deficient number, since it is larger than the sum of its proper divisors (1).
31005441133 is an equidigital number, since it uses as much as digits as its factorization.
31005441133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 31005441133 its reverse (33114450013), we get a palindrome (64119891146).
The spelling of 31005441133 in words is "thirty-one billion, five million, four hundred forty-one thousand, one hundred thirty-three".
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