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31020000041 is a prime number
BaseRepresentation
bin11100111000111011…
…111010001100101001
32222001211121021101102
4130320323322030221
51002012110000131
622130030131145
72145463435622
oct347073721451
988054537342
1031020000041
1112178a88178
126018650ab5
132c047b5714
141703ac0a49
15c1845b1cb
hex738efa329

31020000041 has 2 divisors, whose sum is σ = 31020000042. Its totient is φ = 31020000040.

The previous prime is 31019999993. The next prime is 31020000049. The reversal of 31020000041 is 14000002013.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21309868441 + 9710131600 = 145979^2 + 98540^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31020000041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31019999977 and 31020000031.

It is not a weakly prime, because it can be changed into another prime (31020000049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15510000020 + 15510000021.

It is an arithmetic number, because the mean of its divisors is an integer number (15510000021).

Almost surely, 231020000041 is an apocalyptic number.

It is an amenable number.

31020000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

31020000041 is an equidigital number, since it uses as much as digits as its factorization.

31020000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 11.

Adding to 31020000041 its reverse (14000002013), we get a palindrome (45020002054).

The spelling of 31020000041 in words is "thirty-one billion, twenty million, forty-one", and thus it is an aban number and an uban number.