Base | Representation |
---|---|
bin | 1110000110111000110111… |
… | …01100001000000101011101 |
3 | 11001211202211010202112122121 |
4 | 13003130123230020011131 |
5 | 13031240112403100133 |
6 | 145551435305142541 |
7 | 6351224122260454 |
oct | 703343354100535 |
9 | 131752733675577 |
10 | 31023013331293 |
11 | 9980871291405 |
12 | 359057448aa51 |
13 | 14405c4483b89 |
14 | 793743d91b9b |
15 | 38bea6ad502d |
hex | 1c371bb0815d |
31023013331293 has 2 divisors, whose sum is σ = 31023013331294. Its totient is φ = 31023013331292.
The previous prime is 31023013331279. The next prime is 31023013331341. The reversal of 31023013331293 is 39213331032013.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30199179362884 + 823833968409 = 5495378^2 + 907653^2 .
It is a cyclic number.
It is not a de Polignac number, because 31023013331293 - 29 = 31023013330781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31023013331993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15511506665646 + 15511506665647.
It is an arithmetic number, because the mean of its divisors is an integer number (15511506665647).
Almost surely, 231023013331293 is an apocalyptic number.
It is an amenable number.
31023013331293 is a deficient number, since it is larger than the sum of its proper divisors (1).
31023013331293 is an equidigital number, since it uses as much as digits as its factorization.
31023013331293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 34.
The spelling of 31023013331293 in words is "thirty-one trillion, twenty-three billion, thirteen million, three hundred thirty-one thousand, two hundred ninety-three".
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