Base | Representation |
---|---|
bin | 101101001011000010100… |
… | …111000011001001001111 |
3 | 101222202120020001012220121 |
4 | 231023002213003021033 |
5 | 401324431214412421 |
6 | 10334021512125411 |
7 | 440162514400525 |
oct | 55130247031117 |
9 | 11882506035817 |
10 | 3104231404111 |
11 | a97551778372 |
12 | 421754996867 |
13 | 19695cb92456 |
14 | aa361d06315 |
15 | 55b351b2d41 |
hex | 2d2c29c324f |
3104231404111 has 2 divisors, whose sum is σ = 3104231404112. Its totient is φ = 3104231404110.
The previous prime is 3104231404091. The next prime is 3104231404181. The reversal of 3104231404111 is 1114041324013.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3104231404111 - 219 = 3104230879823 is a prime.
It is a super-2 number, since 2×31042314041112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3104231404181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1552115702055 + 1552115702056.
It is an arithmetic number, because the mean of its divisors is an integer number (1552115702056).
Almost surely, 23104231404111 is an apocalyptic number.
3104231404111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3104231404111 is an equidigital number, since it uses as much as digits as its factorization.
3104231404111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 3104231404111 its reverse (1114041324013), we get a palindrome (4218272728124).
The spelling of 3104231404111 in words is "three trillion, one hundred four billion, two hundred thirty-one million, four hundred four thousand, one hundred eleven".
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