3105010121 has 2 divisors, whose sum is σ = 3105010122. Its totient is φ = 3105010120.

The previous prime is 3105010109. The next prime is 3105010123. The reversal of 3105010121 is 1210105013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2594476096 + 510534025 = 50936^2 + 22595^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3105010121 is a prime.

Together with 3105010123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3105010096 and 3105010105.

It is not a weakly prime, because it can be changed into another prime (3105010123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1552505060 + 1552505061.

It is an arithmetic number, because the mean of its divisors is an integer number (1552505061).

Almost surely, 2^3105010121 is an apocalyptic number.

It is an amenable number.

3105010121 is a deficient number, since it is larger than the sum of its proper divisors (1).

3105010121 is an equidigital number, since it uses as much as digits as its factorization.

3105010121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 3105010121 is about 55722.6176790000. The cubic root of 3105010121 is about 1458.8848244427.

Adding to 3105010121 its reverse (1210105013), we get a palindrome (4315115134).

The spelling of 3105010121 in words is "three billion, one hundred five million, ten thousand, one hundred twenty-one".