Base | Representation |
---|---|
bin | 100011010110110100101110… |
… | …0010001111010100000101111 |
3 | 1111210011022200210102012101212 |
4 | 1012231221130101322200233 |
5 | 311230411231301301333 |
6 | 3021235253140225035 |
7 | 122336006100554432 |
oct | 10655513421724057 |
9 | 1453138623365355 |
10 | 311000130103343 |
11 | 90104461760a5a |
12 | 2aa69aaa39b17b |
13 | 1046c25677c6a5 |
14 | 56b26b5397819 |
15 | 25e4c61667448 |
hex | 11ada5c47a82f |
311000130103343 has 2 divisors, whose sum is σ = 311000130103344. Its totient is φ = 311000130103342.
The previous prime is 311000130103217. The next prime is 311000130103361. The reversal of 311000130103343 is 343301031000113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311000130103343 is a prime.
It is a super-4 number, since 4×3110001301033434 (a number of 59 digits) contains 4444 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311000136103343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155500065051671 + 155500065051672.
It is an arithmetic number, because the mean of its divisors is an integer number (155500065051672).
Almost surely, 2311000130103343 is an apocalyptic number.
311000130103343 is a deficient number, since it is larger than the sum of its proper divisors (1).
311000130103343 is an equidigital number, since it uses as much as digits as its factorization.
311000130103343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 311000130103343 its reverse (343301031000113), we get a palindrome (654301161103456).
The spelling of 311000130103343 in words is "three hundred eleven trillion, one hundred thirty million, one hundred three thousand, three hundred forty-three".
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