311000131020 has 24 divisors (see below), whose sum is σ = 870800367024. Its totient is φ = 82933368256.

The previous prime is 311000131019. The next prime is 311000131051. The reversal of 311000131020 is 20131000113.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 311000130987 and 311000131005.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2591667699 + ... + 2591667818.

It is an arithmetic number, because the mean of its divisors is an integer number (36283348626).

Almost surely, 2^311000131020 is an apocalyptic number.

311000131020 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

311000131020 is an abundant number, since it is smaller than the sum of its proper divisors (559800236004).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311000131020 is a wasteful number, since it uses less digits than its factorization.

311000131020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5183335529 (or 5183335527 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 311000131020 its reverse (20131000113), we get a palindrome (331131131133).

The spelling of 311000131020 in words is "three hundred eleven billion, one hundred thirty-one thousand, twenty".