311004013 has 2 divisors, whose sum is σ = 311004014. Its totient is φ = 311004012.

The previous prime is 311004011. The next prime is 311004037. The reversal of 311004013 is 310400113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 174160809 + 136843204 = 13197^2 + 11698^2 .

It is a cyclic number.

It is not a de Polignac number, because 311004013 - 2¹ = 311004011 is a prime.

It is a super-2 number, since 2×311004013² = 193446992204208338, which contains 22 as substring.

Together with 311004011, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 311003984 and 311004002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311004011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155502006 + 155502007.

It is an arithmetic number, because the mean of its divisors is an integer number (155502007).

Almost surely, 2^311004013 is an apocalyptic number.

It is an amenable number.

311004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

311004013 is an equidigital number, since it uses as much as digits as its factorization.

311004013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 311004013 is about 17635.3058663580. The cubic root of 311004013 is about 677.5198093362.

Adding to 311004013 its reverse (310400113), we get a palindrome (621404126).

The spelling of 311004013 in words is "three hundred eleven million, four thousand, thirteen".