311014213011127 has 2 divisors, whose sum is σ = 311014213011128. Its totient is φ = 311014213011126.

The previous prime is 311014213011113. The next prime is 311014213011133. The reversal of 311014213011127 is 721110312410113.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311014213011127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311014213011095 and 311014213011104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311014213017127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155507106505563 + 155507106505564.

It is an arithmetic number, because the mean of its divisors is an integer number (155507106505564).

Almost surely, 2^{311014213011127} is an apocalyptic number.

311014213011127 is a deficient number, since it is larger than the sum of its proper divisors (1).

311014213011127 is an equidigital number, since it uses as much as digits as its factorization.

311014213011127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 28.

The spelling of 311014213011127 in words is "three hundred eleven trillion, fourteen billion, two hundred thirteen million, eleven thousand, one hundred twenty-seven".