Base | Representation |
---|---|
bin | 101101010001010110101… |
… | …110010110000111101111 |
3 | 102000102001201122020020022 |
4 | 231101112232112013233 |
5 | 401432322343441421 |
6 | 10341102345112355 |
7 | 440522521561253 |
oct | 55212656260757 |
9 | 12012051566208 |
10 | 3111011312111 |
11 | a9a41086661a |
12 | 422b274886bb |
13 | 1974a06c7b31 |
14 | aa806530263 |
15 | 55dd05047ab |
hex | 2d456b961ef |
3111011312111 has 2 divisors, whose sum is σ = 3111011312112. Its totient is φ = 3111011312110.
The previous prime is 3111011312011. The next prime is 3111011312117. The reversal of 3111011312111 is 1112131101113.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3111011312111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3111011312111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3111011312117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555505656055 + 1555505656056.
It is an arithmetic number, because the mean of its divisors is an integer number (1555505656056).
Almost surely, 23111011312111 is an apocalyptic number.
3111011312111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111011312111 is an equidigital number, since it uses as much as digits as its factorization.
3111011312111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 17.
Adding to 3111011312111 its reverse (1112131101113), we get a palindrome (4223142413224).
The spelling of 3111011312111 in words is "three trillion, one hundred eleven billion, eleven million, three hundred twelve thousand, one hundred eleven".
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