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31110113211253 is a prime number
BaseRepresentation
bin1110001001011011000110…
…01111110011001101110101
311002011002122021112212222121
413010231203033303031311
513034202002440230003
6150055442205555541
76360426415113526
oct704554317631565
9132132567485877
1031110113211253
119a047a796137a
1235a5421b75bb1
1314488954c289b
14797a47a4684d
1538e3a354bcbd
hex1c4b633f3375

31110113211253 has 2 divisors, whose sum is σ = 31110113211254. Its totient is φ = 31110113211252.

The previous prime is 31110113211227. The next prime is 31110113211257. The reversal of 31110113211253 is 35211231101113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25933933096369 + 5176180114884 = 5092537^2 + 2275122^2 .

It is a cyclic number.

It is not a de Polignac number, because 31110113211253 - 241 = 28911089955701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31110113211257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15555056605626 + 15555056605627.

It is an arithmetic number, because the mean of its divisors is an integer number (15555056605627).

Almost surely, 231110113211253 is an apocalyptic number.

It is an amenable number.

31110113211253 is a deficient number, since it is larger than the sum of its proper divisors (1).

31110113211253 is an equidigital number, since it uses as much as digits as its factorization.

31110113211253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 25.

Adding to 31110113211253 its reverse (35211231101113), we get a palindrome (66321344312366).

The spelling of 31110113211253 in words is "thirty-one trillion, one hundred ten billion, one hundred thirteen million, two hundred eleven thousand, two hundred fifty-three".