Base | Representation |
---|---|
bin | 11100111110010100… |
… | …000111010100000100 |
3 | 2222022010101111101220 |
4 | 130332110013110010 |
5 | 1002203204400200 |
6 | 22143012120340 |
7 | 2150640413541 |
oct | 347624072404 |
9 | 88263344356 |
10 | 31110231300 |
11 | 12214a07265 |
12 | 60429060b0 |
13 | 2c1a3b89b5 |
14 | 1711a8bbc8 |
15 | c213314a0 |
hex | 73e507504 |
31110231300 has 36 divisors (see below), whose sum is σ = 90012270096. Its totient is φ = 8296061600.
The previous prime is 31110231287. The next prime is 31110231307. The reversal of 31110231300 is 313201113.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 31110231300.
It is not an unprimeable number, because it can be changed into a prime (31110231307) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 51850086 + ... + 51850685.
It is an arithmetic number, because the mean of its divisors is an integer number (2500340836).
Almost surely, 231110231300 is an apocalyptic number.
31110231300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31110231300 is an abundant number, since it is smaller than the sum of its proper divisors (58902038796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31110231300 is a wasteful number, since it uses less digits than its factorization.
31110231300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103700788 (or 103700781 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 31110231300 its reverse (313201113), we get a palindrome (31423432413).
The spelling of 31110231300 in words is "thirty-one billion, one hundred ten million, two hundred thirty-one thousand, three hundred".
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