Base | Representation |
---|---|
bin | 101101010001011000100… |
… | …100101011001001011111 |
3 | 102000102010220000011110121 |
4 | 231101120210223021133 |
5 | 401432403314044411 |
6 | 10341105414015411 |
7 | 440523346333102 |
oct | 55213044531137 |
9 | 12012126004417 |
10 | 3111042331231 |
11 | a9a42732275a |
12 | 422b35947567 |
13 | 1974a6c68943 |
14 | aa80a6c6739 |
15 | 55dd30d0571 |
hex | 2d45892b25f |
3111042331231 has 2 divisors, whose sum is σ = 3111042331232. Its totient is φ = 3111042331230.
The previous prime is 3111042331213. The next prime is 3111042331237. The reversal of 3111042331231 is 1321332401113.
3111042331231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with previous prime (3111042331213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3111042331231 is a prime.
It is a super-3 number, since 3×31110423312313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 3111042331196 and 3111042331205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3111042331237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555521165615 + 1555521165616.
It is an arithmetic number, because the mean of its divisors is an integer number (1555521165616).
Almost surely, 23111042331231 is an apocalyptic number.
3111042331231 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111042331231 is an equidigital number, since it uses as much as digits as its factorization.
3111042331231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 3111042331231 its reverse (1321332401113), we get a palindrome (4432374732344).
The spelling of 3111042331231 in words is "three trillion, one hundred eleven billion, forty-two million, three hundred thirty-one thousand, two hundred thirty-one".
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