Base | Representation |
---|---|
bin | 1110001001011100110001… |
… | …10100111010000111100100 |
3 | 11002011011221221000202110200 |
4 | 13010232120310322013210 |
5 | 13034210323101200200 |
6 | 150100111320550500 |
7 | 6360460611603633 |
oct | 704563064720744 |
9 | 132134857022420 |
10 | 31111012131300 |
11 | 9a05119316302 |
12 | 35a5633022430 |
13 | 14489a97cb83a |
14 | 797ad11a151a |
15 | 38e407413800 |
hex | 1c4b98d3a1e4 |
31111012131300 has 108 divisors (see below), whose sum is σ = 98113995666960. Its totient is φ = 8245372501440.
The previous prime is 31111012131239. The next prime is 31111012131317. The reversal of 31111012131300 is 313121011113.
31111012131300 is a `hidden beast` number, since 311 + 1 + 1 + 0 + 1 + 21 + 31 + 300 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 105889470 + ... + 106182869.
Almost surely, 231111012131300 is an apocalyptic number.
31111012131300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31111012131300 is an abundant number, since it is smaller than the sum of its proper divisors (67002983535660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31111012131300 is a wasteful number, since it uses less digits than its factorization.
31111012131300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212072522 (or 212072512 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 31111012131300 its reverse (313121011113), we get a palindrome (31424133142413).
The spelling of 31111012131300 in words is "thirty-one trillion, one hundred eleven billion, twelve million, one hundred thirty-one thousand, three hundred".
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